# 感冒

2014/09/2622:39:15 发表评论 2,260 次

[latex]$\frac{{{G_1}}}{{{G_0}}} = \sqrt {\frac{{P_{01}^2 - P_{g1}^2}}{{P_0^2 - P_g^2}}} * \sqrt {\frac{{{T_0}}}{{{T_{01}}}}}$

When $a \ne 0$ , there are two solutions to $$ax^2 + bx + c = 0$$ and they are
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$